Optics Question 101

Question: A ray of light travels from an optically denser to rarer medium. The critical angle for the two media is C. The maximum possible deviation of the ray will be

[KCET (Engg./Med.) 2002]

Options:

A) $ ( \frac{\pi }{2}-C ) $

B) 2C

C) $ \pi -2C $

D) $ \pi -C $

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Answer:

Correct Answer: C

Solution:

When the ray passes into the rarer medium, the deviation is $ \delta =\varphi -0 $ .

This can have a maximum value of $ ( \frac{\pi }{2}-C ) $ for $ \theta =C $ and $ \varphi =\frac{\pi }{2} $ .

When total internal reflection occurs, the deviation is $ \delta =\pi -2 $ , the minimum value of $ \theta $ being $ C. $

The maximum value of $ \delta =\pi -2C $ .



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