Laws Of Motion Question 81

Question: Two forces are such that the sum of their magnitudes is 18 N and their resultant is perpendicular to the smaller force and magnitude of resultant is 12 N. Then the magnitudes of the forces are [AIEEE 2002]

Options:

A) 12 N, 6 N

B) 13 N, 5N

C) 10 N, 8 N

D) 16 N, 2 N

Show Answer

Answer:

Correct Answer: B

Solution:

A+B=18 -(i)

12=A2+B2+2ABcosθ -(ii)

tanα=BsinθA+Bcosθ=tan90

therefore cosθ=AB -(iii) By solving (i), (ii) and (iii), A=13N

and B=5N



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