Laws Of Motion Question 71

Question: A stick of 1 m is moving with velocity of $ 2.7\times 10^{8}m{{s}^{-1}} $ . What is the apparent length of the stick $ (c=3\times 10^{8}m{{s}^{-1}}) $ [BHU 1995]

Options:

A) 10 m

B) 0.22 m

C) 0.44 m

D) 2.4 m

Show Answer

Answer:

Correct Answer: C

Solution:

$ l=l _{0}\sqrt{1-\frac{v^{2}}{c^{2}}} $

$ =1\sqrt{1-{{( \frac{2.7\times 10^{8}}{3\times 10^{8}} )}^{2}}}\Rightarrow l=0.44\ m $



NCERT Chapter Video Solution

Dual Pane