Laws Of Motion Question 64

Question: When forces F1,F2,F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed then the acceleration of the particle is [AIEEE 2002]

Options:

A) F1/m

B) F2F3/mF1

C) (F2−F3)/m

D) F2/m

Show Answer

Answer:

Correct Answer: A

Solution:

For equilibrium of system, F1=F22+F32 As θ=90∘ In the absence of force F1 ,

Acceleration =Net forcem

=F22+F32m=F1m

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