Laws Of Motion Question 55

Question: A block P of mass m is placed on a frictionless horizontal surface. Another block Q of same mass is kept on P and connected to the wall with the help of a spring of spring constant k. μs is the coefficient of friction between P and Q. The blocks move together performing SHM of amplitude A. The maximum value of the friction force between P and Q is[IIT-JEE (Screening) 2004]

Options:

A) kA

B) kA2

C) Zero

D) μsmg

Show Answer

Answer:

Correct Answer: B

Solution:

When two blocks performs simple harmonic motion together then at the extreme position ( at amplitude =A) Restoring force F=KA=2ma

therefore a=KA2m

There will be no relative motion between P and Q if pseudo force on block P is less than or just equal to limiting friction between P and Q. i.e. m (KA2m)= Limiting friction Maximum friction =KA2



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