Laws Of Motion Question 48

Question: A bullet of mass 0.1 kg is fired with a speed of 100 m/sec, the mass of gun is 50 kg. The velocity of recoil is [AFMC 1995; JIPMER 2000; Pb.PMT 2002]

Options:

A) 0.2 m/sec

B) 0.1 m/sec

C) 0.5 m/sec

D) 0.05 m/sec

Show Answer

Answer:

Correct Answer: A

Solution:

According to principle of conservation of linear momentum, $ m _{G}v _{G}=m _{B}v _{B} $

$ \Rightarrow $ $ v _{G}=\frac{m _{B}v _{B}}{m _{G}}=\frac{0.1\times 10^{2}}{50}=0.2m/s $



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