Laws Of Motion Question 44

Question: A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulse is [AFMC 1998]

Options:

A) $ 0.15\times {{10}^{-3}}Ns $

B) $ 0.98\times {{10}^{-3}}Ns $

C) $ 1.5\times {{10}^{-3}}Ns $

D) $ 2.5\times {{10}^{-3}}Ns $

Show Answer

Answer:

Correct Answer: C

Solution:

Impulse, $ I=F\times \Delta t=50\times {{10}^{-5}}\times 3 $ =$ 1.5\times {{10}^{-3}}\ N\text{-}s $



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