SATHEE: Laws Of Motion Question 44

Laws Of Motion Question 44

Question: A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulse is [AFMC 1998]

Options:

A) $0.15 \times 10^{- 3} N s$

B) $0.98 \times 10^{- 3} N s$

C) $1.5 \times 10^{- 3} N s$

D) $2.5 \times 10^{- 3} N s$

Show Answer

Answer:

Correct Answer: C

Solution:

Impulse, $I = F \times Δ t = 50 \times 10^{- 5} \times 3$ = $1.5 \times 10^{- 3} N - s$

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