SATHEE: Laws Of Motion Question 425

Laws Of Motion Question 425

Question: A spring is compressed between blocks of masses $m_{1}$ and $m_{2}$ placed on a smooth horizontal surface . When the blocks are release, they have initial velocity of $v_{1}$ and $v_{2}$ in the direction shown. The blocks travel distances $x_{1}$ and $x_{2}$ before coming to rest. The ratio of $\frac{x_{1}}{x_{2}}$ is

Options:

A) $\frac{m_{1}}{m_{2}}$

B) $\sqrt{\frac{m_{1}}{m_{2}}}$

C) $\frac{m_{2}}{m_{1}}$

D) $\sqrt{\frac{m_{2}}{m_{1}}}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] From linear momentum conservation, $m_{1} v_{1} = m_{2} v_{2}$ .

As they move spring exerts equal and opposite forces on $m_{1}$ and $m_{2}$ .

$\Rightarrow$ $m_{1} \frac{d x_{1}}{d t} = m_{2} \frac{d x_{2}}{d t}$

$\Rightarrow$ $m_{1} \int d x_{1} = m_{2} \int d x_{2}$

$\Rightarrow$ $m_{1} x_{1} = m_{2} x_{2}$

$\Rightarrow$ $\frac{x_{1}}{x_{2}} = \frac{m_{2}}{m_{1}}$

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Laws Of Motion Question 425

Question: A spring is compressed between blocks of masses m1 and m2 placed on a smooth horizontal surface . When the blocks are release, they have initial velocity of v1 and v2 in the direction shown. The blocks travel distances x1 and x2 before coming to rest. The ratio of x1x2 is

Options:

Answer:

Solution:

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