SATHEE: Laws Of Motion Question 421

Laws Of Motion Question 421

Question: Two masses $m_{1}$ and $m_{2}$ which are connected with a light string, are placed over a frictionless pulley. This set up is placed over a weighing machine, as shown. Three combination of masses $m_{1}$ and $m_{2}$ are used, in first case $m_{1} = 6 k g$ and $m_{2} = 2 k g,$ in second case $m_{1} = 5 k g$ and $m_{2} = 3 k g$ and in third case $m_{1} = 4 k g$ and $m_{2} = 4 k g$ . Masses are held stationary initially and then released. If the readings of the weighing machine after the release in three cases are $W_{1}, W_{2}$ and $W_{3}$ respectively then:

Options:

A) $W_{1} > W_{2} > W_{3}$

B) $W_{1} < W_{2} < W_{3}$

C) $W_{1} = W_{2} = W_{3}$

D) $W_{1} = W_{2} < W_{3}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Reading of the weighing machine $= 2 T +$ weight of the machine.

As weight of the machine is constant. $T = \frac{2 m_{1} m_{2}}{m_{1} + m_{2}}$

So reading is maximum for the case $m_{1} m_{2}$ is maximum as $m_{1} m_{2}$ in all cases is same.

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