Laws Of Motion Question 42

Question: A man fires a bullet of mass 200 g at a speed of 5 m/s. The gun is of one kg mass. by what velocity the gun rebounds backwards [CBSE PMT 1996; JIPMER 2000]

Options:

A) 0.1 m/s

B) 10 m/s

C) 1 m/s

D) 0.01 m/s

Show Answer

Answer:

Correct Answer: C

Solution:

$ v _{G}=\frac{m _{B}v _{B}}{m _{G}}=\frac{0.2\times 5}{1}=1\ m/s $



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