Laws Of Motion Question 411

Question: A perfectly straight portion of a uniform rope has mass M and length L. At end A of the segment, the tension in the rope is TA and at end B it is TB(TB>TA) . Neglect effect of gravity and no contact force acts on the rope in between points A and B. The tension in the rope at a distance L/5 from end A is

Options:

A) TBTA

B) (TA+TB)/5

C) (4TA+TB)/5

D) (TATB)/5

Show Answer

Answer:

Correct Answer: C

Solution:

The F.B.D. of section of rope between A and B having acceleration a towards left is

Applying Newton’s second law on section AB and section AC of rope we get

TBTA=Ma and TCTA=M5a

Solving TC=TB+4TA5



NCERT Chapter Video Solution

Dual Pane