Laws Of Motion Question 406

Question: A boy of mass m is sliding down a vertical pole by pressing it with a horizontal force F. If μ is the coefficient of friction between his palms and the pole, the acceleration with which he slides down is

Options:

A) g

B) μFm

C) g+μFm

D) gμFm

Show Answer

Answer:

Correct Answer: D

Solution:

Here, normal contact force N=F and friction force, f=μN

So the free body diagram of boy is as shown adjacent in the above figure.

Now, ma=mgf

a=gμFm



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