SATHEE: Laws Of Motion Question 405

Laws Of Motion Question 405

Question: A block A is kept on a block B. Friction between B and ground is negligible. $μ_{s}$ and $μ_{K}$ are the coefficients of static and kinetic friction between A and B, respectively. A horizontal force F is applied on A. $a_{1}$ is the acceleration of B just before A slips on B and $a_{2}$ is the acceleration of B after A slips on B. Assume $μ_{s} > μ_{K}$ . Then

Options:

A) $a_{1} > a_{2}$

B) $a_{1} < a_{2}$

C) $a_{1} = a_{2}$

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

Just before slipping occurs force acting on B is, $μ_{s} m g$ , where m is the mass of block A. After the slipping the force on block B is $μ_{K} m g$ .

Force before slipping is more, so acceleration before slipping should be more.

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Laws Of Motion Question 405

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