SATHEE: Laws Of Motion Question 392

Laws Of Motion Question 392

Question: What is the minimum stopping distance for a vehicle of mass m moving with speed v along a level road. If the coefficient of friction between the tyres and the road is $x = 40 c m$

Options:

A) $\frac{v^{2}}{2 μ g}$

B) $\frac{2 v^{2}}{μ g}$

C) $\frac{v^{2}}{μ g}$

D) none of these

Show Answer

Answer:

Correct Answer: A

Solution:

$0^{2} = V^{2} - 2 μ g s$

$\Rightarrow s = \frac{V^{2}}{2 μ g}$ [a].

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Laws Of Motion Question 392

Question: What is the minimum stopping distance for a vehicle of mass m moving with speed v along a level road. If the coefficient of friction between the tyres and the road is x=40cm

Options:

Answer:

Solution:

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Question: What is the minimum stopping distance for a vehicle of mass m moving with speed v along a level road. If the coefficient of friction between the tyres and the road is $x = 40 c m$