SATHEE: Laws Of Motion Question 391

Laws Of Motion Question 391

Question: A weight w is to be moved from the bottom to the top of an inclined plane of inclination 9 to the horizontal. If a smaller force is to be applied to drag it along the plane in comparison to lift it vertically up, the coefficient of friction should be such that:

Options:

A) $μ > \tan (\frac{π}{4} - \frac{θ}{2})$

B) $μ < \tan (\frac{π}{4} - \frac{θ}{2})$

C) $μ < \tan θ$

D) $μ > \tan \frac{π}{4}$

Show Answer

Answer:

Correct Answer: B

Solution:

$F_{1} = w \sin θ + μ w \cos θ$

$F_{2} = w$

As, $F_{1} < F_{2}$

$∴ μ < \tan (\frac{π}{4} = \frac{θ}{2})$

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Laws Of Motion Question 391

Question: A weight w is to be moved from the bottom to the top of an inclined plane of inclination 9 to the horizontal. If a smaller force is to be applied to drag it along the plane in comparison to lift it vertically up, the coefficient of friction should be such that:

Options:

Answer:

Solution:

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