Laws Of Motion Question 39

Question: A rope of length 5m is kept on frictionless surface and a force of 5N is applied to one of its end. Find tension in the rope at 1m from this end [RPET 2000]

Options:

A) 1 N

B) 3 N

C) 4 N

D) 5 N

Show Answer

Answer:

Correct Answer: C

Solution:

$ T=\frac{F(L-x)}{L}=\frac{5(5-1)}{5}=4N $



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