Laws Of Motion Question 39
Question: A rope of length 5m is kept on frictionless surface and a force of 5N is applied to one of its end. Find tension in the rope at 1m from this end [RPET 2000]
Options:
A) 1 N
B) 3 N
C) 4 N
D) 5 N
Show Answer
Answer:
Correct Answer: C
Solution:
$ T=\frac{F(L-x)}{L}=\frac{5(5-1)}{5}=4N $
