Laws Of Motion Question 386

Question: The time taken by a body in sliding down a rough inclined plane of angle of inclination 45 is n times the time taken by the same body in slipping down a similar frictionless plane. The coefficient of dynamic friction between the body and the plane will be

Options:

A) 1/(1n2)

B) 1(1/n2)

C) Ö1(1/n2)

D) Ö1/(1n2)

Show Answer

Answer:

Correct Answer: B

Solution:

Acceleration when there is no friction is a=gsinθ and acceleration when friction is there is

a=(gsinθμgcosθ)

We know that s=ut+12at2, under condition of u=0,

gives,t=(2s/a) .

Therefore tt=(a/a) .

For our case we get

n=[gsinθ/(gsinθμgcosθ)]

n2=gsinθ/(gsinθμgcosθ)=1/(1μcotθ) but θ=45o

cotθ=1n2=1/(1μ) orμ=1(1/n2)



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