SATHEE: Laws Of Motion Question 384

Laws Of Motion Question 384

Question: Let $\frac{1}{2 \sqrt{3}} \sec$ be the coefficient of friction between blocks of mass m and M. The pulleys are frictionless and strings are massless. Acceleration of mass m is

Options:

A) $\frac{\sqrt{5} m g}{M + \sqrt{5} m + 2 μ m}$

B) $\frac{2 m g}{m + 5 M + 2 μ m}$

C) $\frac{2 \sqrt{5} m g}{M + 5 M + 2 μ m}$

D) $\frac{5 \sqrt{2} m g}{M + \sqrt{5} m + \sqrt{2} μ m}$

Show Answer

Answer:

Correct Answer: C

Solution:

From the constraint net acceleration

$m = \sqrt{a^{2} + {(2 a)}^{2}} = \sqrt{5} a$

$m g = T - μ N = 2 m a$

$N = m a$

$2 T = (M + m) a$

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Laws Of Motion Question 384

Question: Let 123sec be the coefficient of friction between blocks of mass m and M. The pulleys are frictionless and strings are massless. Acceleration of mass m is

Options:

Answer:

Solution:

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Question: Let $\frac{1}{2 \sqrt{3}} \sec$ be the coefficient of friction between blocks of mass m and M. The pulleys are frictionless and strings are massless. Acceleration of mass m is