SATHEE: Laws Of Motion Question 348

Laws Of Motion Question 348

Question: A car is negotiating a curved road of radius R. The road is banked at an angle $θ$ . The coefficient of friction between the tyres of the car and the road is $μ_{s}$ . The maximum safe velocity on this road is:

Options:

A) $\sqrt{g R^{2} \frac{μ_{s} + \tan θ}{1 - μ_{s} \tan θ}}$

B) $\sqrt{g R \frac{μ_{s} + \tan θ}{1 - μ_{s} \tan θ}}$

C) $\sqrt{\frac{g}{R} \frac{μ_{s} + \tan θ}{1 - μ_{s} \tan θ}}$

D) $\sqrt{\frac{g}{R^{2}} \frac{μ_{s} + \tan θ}{1 - μ_{s} \tan θ}}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] On a banked road, $\frac{v^{2} max}{R g} = (\frac{μ_{s} + \tan θ}{1 - μ_{s} \tan θ})$ Maximum safe velocity of a car on the banked road $V_{max} = \sqrt{R g [\frac{μ_{s} + \tan θ}{1 - μ_{s} \tan θ}]}$

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Laws Of Motion Question 348

Question: A car is negotiating a curved road of radius R. The road is banked at an angleθ . The coefficient of friction between the tyres of the car and the road isμs . The maximum safe velocity on this road is:

Options:

Answer:

Solution:

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Question: A car is negotiating a curved road of radius R. The road is banked at an angle $θ$ . The coefficient of friction between the tyres of the car and the road is $μ_{s}$ . The maximum safe velocity on this road is: