Laws Of Motion Question 347

Question: A conical pendulum of length 1 m makes an angle θ=45 w.r.t. Z-axis and moves in a circle in the XY plane. The radius of the circle is 0.4 m and its center is vertically below 0. The speed of the pendulum, in its circular path, will be: (Take g=10ms2 )

Options:

A) 0.4 m/s

B) 4 m/s

C) 0.2 m/s

D) 2 m/s

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Given,θ=45,r=0.4m,g=10m/s2

Tsinθ=mv2r …… (i)

Tcosθ=mg …… (ii)From equation (i) & (ii) we have,tanθ=v2rg

v2=rg  θ=45

Hence, speed of the pendulum in its circular path, v=rg=0.4×10=2m/s



NCERT Chapter Video Solution

Dual Pane