SATHEE: Laws Of Motion Question 342

Laws Of Motion Question 342

Question: A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The angle made by the wire with the vertical is

Options:

A) $0^{\circ}$

B) $\frac{π}{3}$

C) $\frac{π}{6}$

D) $\frac{π}{4}$

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Answer:

Correct Answer: D

Solution:

[d] Given; $s p e e d = 10 m / s;$ radius $r = 10 m$ Angle made by the wire with the vertical $\tan θ = \frac{v^{2}}{r g} = \frac{10^{2}}{10 \times 10} = 1 \Rightarrow θ = 45^{o} = \frac{π}{4}$

Laws Of Motion Question 342

Question: A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The angle made by the wire with the vertical is

Options:

Answer:

Solution:

Engineering Preparation

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NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

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Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Laws Of Motion Question 342

Question: A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The angle made by the wire with the vertical is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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