SATHEE: Laws Of Motion Question 333

Laws Of Motion Question 333

Question: The minimum force required to start pushing a body up rough (frictional coefficient u) inclined plane is $F_{1}$ while the minimum force needed to prevent it from sliding down is $F_{2}$ . If the inclined plane makes an angle $θ$ from the horizontal such that $\tan θ = 2 μ$ then the ratio $\frac{F_{1}}{F_{2}}$ is

Options:

A) 1

B) 2

C) 3

D) 4

Show Answer

Answer:

Correct Answer: C

Solution:

[c] For the upward motion of the body $m g s i n θ + f_{1} = F_{1}$

or, $F_{1} = m g s i n θ + μ m g c o s θ$

For the downward motion of the body, $m g s i n θ - f_{2} = F_{2}$

$o r F_{2} = m g s i n θ - μ m g c o s θ$

$∴ \frac{F_{1}}{F_{2}} = \frac{s i n θ + μ c o s θ}{s i n θ - μ c o s θ}$

$\Rightarrow \frac{\tan θ + μ}{\tan θ - μ} = \frac{2 μ + μ}{2 μ - μ} = \frac{3 μ}{μ} = 3$

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Laws Of Motion Question 333

Question: The minimum force required to start pushing a body up rough (frictional coefficient u) inclined plane is F1 while the minimum force needed to prevent it from sliding down isF2 . If the inclined plane makes an angle θ from the horizontal such thattan⁡θ=2μ then the ratio F1F2 is

Options:

Answer:

Solution:

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