SATHEE: Laws Of Motion Question 331

Laws Of Motion Question 331

Question: A small mass slides down a fixed inclined plane of inclination 6 with the horizontal. The coefficient of friction is $μ = μ_{0} x$ Where $x$ is the distance through which the mass slides down and $μ_{0}$ is a constant? Then he speed is maximum after the mass covers a distance of

Options:

A) $\frac{\cos θ}{μ_{0}}$

B) $\frac{\sin θ}{μ_{0}}$

C) $\frac{t a n θ}{μ_{0}}$

D) $\frac{2 t a n θ}{μ_{0}}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Acceleration of mass at distance x

$a = g (\sin θ - μ_{0} x \cos θ)$

Speed is maximum, when $a = 0$

$g (s i n θ - μ_{0} x c o s θ) = 0$

$x = \frac{\tan θ}{μ_{0}}$

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Laws Of Motion Question 331

Question: A small mass slides down a fixed inclined plane of inclination 6 with the horizontal. The coefficient of friction is μ=μ0x Where x is the distance through which the mass slides down and μ0 is a constant? Then he speed is maximum after the mass covers a distance of

Options:

Answer:

Solution:

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Question: A small mass slides down a fixed inclined plane of inclination 6 with the horizontal. The coefficient of friction is $μ = μ_{0} x$ Where $x$ is the distance through which the mass slides down and $μ_{0}$ is a constant? Then he speed is maximum after the mass covers a distance of