Laws Of Motion Question 314
Question: A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 g is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope? $ ( g=10m/s^{2} ) $
Options:
A) $ 2.5m/s $
B) $ 5m/s^{2} $
C) $ \text{10 }m/s^{2} $
D) $ \text{25 }m/s^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ T= $ Tension caused in string by monkey $ =m( g+a ) $
$ \therefore T\le 25\times 10\Rightarrow 20( 10+a )\le 250 $ or, $ 10+a12.5\Rightarrow a\le 2.5 $
