Laws Of Motion Question 293

Question: A particle moves in the X-Y plane under the influence of force such that its linear momentum isp(t)=A[i^cos(kt)j^sin(kt)] , where A and k are constants. The angle between the force and the momentum is

Options:

A) 0

B) 30

C) 45

D) 90

Show Answer

Answer:

Correct Answer: D

Solution:

[d] p(t)=A[i^cos(kt)j^sin(kt)]

F=dpdt=Ak[i^cos(kt)j^sin(kt)]

Here, F.P=0 but F.P=Fpcosθ

cosθ=0θ=90



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