Laws Of Motion Question 290

Question: The force required to stop a car of mass 800 kg, moving at a speed of $ 20m{{s}^{-1}} $ over a distance of 25m in 2.5 sec is

Options:

A) 1200N

B) 6400 N

C) 1600N

D) 1800N

Show Answer

Answer:

Correct Answer: B

Solution:

[b] As we know, $ |a|=| \frac{v^{2}-u^{2}}{2S} |=\frac{400}{50}=8\text{ m/}{{s}^{2}}. $ So force required $ =F=ma $

$ =800\times 8=6400N $



NCERT Chapter Video Solution

Dual Pane