Laws Of Motion Question 285

Question: A block of mass m is placed on a smooth wedge of inclination 6. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

Options:

A) mg/cosθ

B) mgcosθ

C) mg sinθ

D) mg

Show Answer

Answer:

Correct Answer: A

Solution:

[a] N=masinθ+mgcosθ ……(1)

Also mgsinθ=macosθ ……(2) from (2) a=gtanθ

N=mgsin2θcosθ+mgcosθ,

or N=mgcosθ



NCERT Chapter Video Solution

Dual Pane