Laws Of Motion Question 282

Question: A player stops a football weighting 0.5 kg which comes flying towards him with a velocity of 10m/ s. If the impact lasts for 1/50th sec. and the ball bounces back with a velocity of 15 m/s, then the average force involved is

Options:

A) 250 N

B) 1250 N

C) 500 N

D) 625 N

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Here m=0.5kg; u=10m/s;

[t = 1/50s;v=+15ms1]Force=m(vu)/t=0.5(10+15)×50 =625N



NCERT Chapter Video Solution

Dual Pane