Laws Of Motion Question 237

Question: A man weighs $ 80kg. $ He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $ 5m/s^{2}. $ What would be the reading on the scale. $ (g=10m/s^{2}) $ [CBSE PMT 2003]

Options:

A) 400 N

B) 800 N

C) 1200 N

D) Zero

Show Answer

Answer:

Correct Answer: C

Solution:

For accelerated upward motion $ R=m(g+a)=80(10+5)=1200N $



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