Laws Of Motion Question 200

Question: The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ?a? is 3 : 2. The value of ?a? is (g-Acceleration due to gravity of the earth) [MP PET 1997]

Options:

A) $ \frac{3}{2}g $

B) $ \frac{g}{3} $

C) $ \frac{2}{3}g $

D) g

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{mg}{m(g-a)}=\frac{3}{2} $

therefore $ a=g/3 $



NCERT Chapter Video Solution

Dual Pane