Laws Of Motion Question 194

Question: A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg. If the lift is accelerated upwards with an acceleration of $ 2m/s^{2} $ , then the weight recorded in the machine will be $ (g=10m/s^{2}) $ [MP PMT 1994]

Options:

A) 32 kg

B) 40 kg

C) 42 kg

D) 48 kg

Show Answer

Answer:

Correct Answer: D

Solution:

In stationary lift man weighs 40 kg i.e. 400 N. When lift accelerates upward it’s apparent weight $ =m(g+a) $

$ =40(10+2)=480\ N $ i.e. 48 kg For the clarity of concepts in this problem kg-wt can be used in place of kg.



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