SATHEE: Laws Of Motion Question 135

Laws Of Motion Question 135

Question: A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8, then the ratio of the masses is

Options:

A) 8 : 1

B) 9 : 7

C) 4 : 3

D) 5 : 3

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Answer:

Correct Answer: B

Solution:

[b] From F.B.D. of $m_{1} : T - m_{1} g = m_{1} a$ (i) From F.B.D. of $m_{2} : m_{2} g - T = m_{2} a$ (ii) From (i) and (ii), $a = (\frac{m_{2} - m_{1}}{m_{1} + m_{2}}) g$

$\Rightarrow \frac{g}{8} = (\frac{m_{2} - m_{1}}{m_{1} + m_{2}}) g \Rightarrow \frac{m_{2}}{m_{1}} = \frac{9}{7}$

Laws Of Motion Question 135

Question: A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8, then the ratio of the masses is

Options:

Answer:

Solution:

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Laws Of Motion Question 135

Question: A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the system is g/8, then the ratio of the masses is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is g/8, then the ratio of the masses is