Laws Of Motion Question 130

Question: A bullet of mass w moving with velocity v0 hits a wooden plank A of mass M placed on a smooth horizontal surface. The length of the plank is . The bullet experiences a constant resistive force F inside the block. The minimum value of v0 such that it is able to come out of the plank is

Options:

A) F/mM2

B) 2F(M+m)Mm& 

C)2FmM2& 

D) F(M+m)Mm

Show Answer

Answer:

Correct Answer: B

Solution:

[b] From Newton’s third law a force F acts on the block in forward direction. Acceleration of black a1=FM Retardation of bullet a2=Fm Relative retardation of bullet ar=a1+a2=F(M+m)Mm Applying v2=u22ar

0=v022F(M+m)Mm. Therefore, minimum value of V0 is Or V0=2F(M+m)Mm



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