SATHEE: Laws Of Motion Question 127

Laws Of Motion Question 127

Question: A cylinder of 10 kg is sliding in a plane with an initial velocity of 10 m/s. If the coefficient of friction between the surface and cylinder is 0.5 then before stopping, it will cover. $(g = 10 m / s^{2})$ [Pb. PMT 2004]

Options:

A)2.5 m

B)5 m

C)7.5 m

D)10 m

Show Answer

Answer:

Correct Answer: D

Solution:

Kinetic energy of the cylinder will go against friction $∴$ $\frac{1}{2} m v^{2}$ = $μ m g s$ therefore $s = \frac{u^{2}}{2 μ g} = \frac{{(10)}^{2}}{2 \times (0.5) \times 10} = 10 m$

Laws Of Motion Question 127

Question: A cylinder of 10 kg is sliding in a plane with an initial velocity of 10 m/s. If the coefficient of friction between the surface and cylinder is 0.5 then before stopping, it will cover. $(g = 10 m / s^{2})$ [Pb. PMT 2004]

Options:

Answer:

Solution:

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Laws Of Motion Question 127

Question: A cylinder of 10 kg is sliding in a plane with an initial velocity of 10 m/s. If the coefficient of friction between the surface and cylinder is 0.5 then before stopping, it will cover. (g=10m/s2) [Pb. PMT 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A cylinder of 10 kg is sliding in a plane with an initial velocity of 10 m/s. If the coefficient of friction between the surface and cylinder is 0.5 then before stopping, it will cover. $(g = 10 m / s^{2})$ [Pb. PMT 2004]