Laws Of Motion Question 119

Question: A horizontal force of 129.4 N is applied on a 10 kg block which rests on a horizontal surface. If the coefficient of friction is 0.3, the acceleration should be

Options:

A) 9.8m/s2

B) 10m/s2

C) 12.6m/s2

D) 19.6m/s2

Show Answer

Answer:

Correct Answer: B

Solution:

From the relation Fμmg=ma

a=Fμmgm=129.40.3×10×9.810=10 m/s2



NCERT Chapter Video Solution

Dual Pane