Laws Of Motion Question 118

Question: A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10s.Then the coefficient of friction is [AIEEE 2003]

Options:

A) 0.01

B) 0.02

C) 0.03

D) 0.06

Show Answer

Answer:

Correct Answer: D

Solution:

v=uatuμgt=0

μ=ugt=610×10=0.06



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