SATHEE: Laws Of Motion Question 104

Laws Of Motion Question 104

Question: A 60 kg body is pushed with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static friction and sliding friction are 0.5 and 0.4 respectively. The acceleration of the body is

Options:

A) $6 m / s^{2}$

B) $4.9 m / s^{2}$

C) $3.92 m / s^{2}$

D) $1 m / s^{2}$

Show Answer

Answer:

Correct Answer: D

Solution:

Limiting friction $= μ_{s} R = μ_{s} m g = 0.5 \times 60 \times 10 = 300 N$ Kinetic friction $= μ_{k} R = μ_{k} m g = 0.4 \times 60 \times 10 = 240 N$ Force applied on the body = 300 N and if the body is moving then, Net accelerating force=Applied force ? Kinetic frictiontherefore $m a = 300 - 240 = 60$

$∴$ $a = \frac{60}{60} = 1 m / s^{2}$

Laws Of Motion Question 104

Question: A 60 kg body is pushed with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static friction and sliding friction are 0.5 and 0.4 respectively. The acceleration of the body is

Options:

Answer:

Solution:

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Laws Of Motion Question 104

Question: A 60 kg body is pushed with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static friction and sliding friction are 0.5 and 0.4 respectively. The acceleration of the body is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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