Laws Of Motion Question 101

Question: A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.20. The amount of heat generated in 5 sec is $ (J=4.2joule/cal $ and $ g=9.8m/s^{2}) $ [MH CET (Med.) 2001]

Options:

A) 9.33 cal

B) 10.21 cal

C) 12.67 cal

D) 13.34 cal

Show Answer

Answer:

Correct Answer: A

Solution:

Work done = Force × Displacement$ =\mu \ mg\times (v\times t) $

$ W=(0.2)\times 2\times 9.8\times 2\times 5\ joule $ Heat generated Q$ =\frac{W}{J} $

$ =\frac{0.2\times 2\times 9.8\times 2\times 5}{4.2} $

$ =9.33 $ cal



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