SATHEE: Kinematics Question 789

Kinematics Question 789

Question: If the radius of curvature of the path of two particles of same masses are in the ratio 1 : 2, then in order to have constant centripetal force, their velocity, should be in the ratio of [Pb. PET 2000]

Options:

A) 1 : 4

B) 4 : 1

C) $\sqrt{2} : 1$

D) $1 : \sqrt{2}$

Show Answer

Answer:

Correct Answer: D

Solution:

The centripetal force, $F = \frac{m v^{2}}{r}$

therefore $r = \frac{m v^{2}}{F}$

$r \propto v^{2}$ or $v \propto \sqrt{r}$

(If m and F are constant), therefore $\frac{v_{1}}{v_{2}} = \sqrt{\frac{r_{1}}{r_{2}}} = \sqrt{\frac{1}{2}}$

Privacy Policy

Powered by Prutor@IITK

sathee@iitk.ac.in

Media coverage of SATHEE

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Kinematics Question 789

Question: If the radius of curvature of the path of two particles of same masses are in the ratio 1 : 2, then in order to have constant centripetal force, their velocity, should be in the ratio of [Pb. PET 2000]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu