Kinematics Question 783
Question: A proton of mass 1.6 × 10^27 kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4 × 10?13 N.then the frequency of revolution of the proton is about [Kerala (Med.) 2002]
Options:
A) 0.08 × 108 cycles per sec
B) 4 × 108 cycles per sec
C) 8 × 108 cycles per sec
D) 12 × 108 cycles per sec
Show Answer
Answer:
Correct Answer: A
Solution:
$ m4{{\pi }^{2}}n^{2}r=4\times {{10}^{-13}} $
therefore $ n=0.08\times 10^{8}cycles/\sec . $
