Kinematics Question 783

Question: A proton of mass 1.6 × 10^27 kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4 × 10?13 N.then the frequency of revolution of the proton is about [Kerala (Med.) 2002]

Options:

A) 0.08 × 108 cycles per sec

B) 4 × 108 cycles per sec

C) 8 × 108 cycles per sec

D) 12 × 108 cycles per sec

Show Answer

Answer:

Correct Answer: A

Solution:

$ m4{{\pi }^{2}}n^{2}r=4\times {{10}^{-13}} $

therefore $ n=0.08\times 10^{8}cycles/\sec . $



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