Kinematics Question 745

Question: The second’s hand of a watch has length 6 cm. Speed of end point and magnitude of difference of velocities at two perpendicular positions will be [RPET 1997]

Options:

A) 6.28 and 0 mm/s

B) 8.88 and 4.44 mm/s

C) 8.88 and 6.28 mm/s

D) 6.28 and 8.88 mm/s

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Answer:

Correct Answer: D

Solution:

v=rω=r×2πT=0.06×2π60=6.28mm/s Magnitude of change in velocity =|v2v1|

=v12+v22=8.88mm/s

(As v1=v2=6.28mm/s)



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