Kinematics Question 724

Question: A road is 10 m wide. it’s radius of curvature it’s 50 m. The outer edge it’s above the lower edge by a distance of 1.5 m. this road is most suited for the velocity

Options:

A) 2.5 m/sec

B)4.5 m/sec

C) 6.5 m/sec

D)8.5 m/sec

Show Answer

Answer:

Correct Answer: D

Solution:

$ \frac{v^{2}}{rg}=\frac{h}{l} $

therefore $ v=\sqrt{\frac{rgh}{l}} $

$ =\sqrt{\frac{50\times 1.5\times 9.8}{10}}=8.57m/s $



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