SATHEE: Kinematics Question 673

Kinematics Question 673

Question: A body is thrown horizontally from the top of a tower of height 5 m.It touches the ground at a distance of 10 m from the foot of the tower.The initial velocity of the body is $(g = 10 m s^{2})$

Options:

A) $2.5 m s^{1}$

B) $5 m s^{1}$

C) $10 m s^{1}$

D) $20 m s^{1}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $S = u \times \sqrt{\frac{2 h}{g}}$

therefore $10 = u \sqrt{2 \times \frac{5}{10}}$

therefore $u = 10 m / s$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Kinematics Question 673

Question: A body is thrown horizontally from the top of a tower of height 5 m.It touches the ground at a distance of 10 m from the foot of the tower.The initial velocity of the body is (g=10ms2)

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: A body is thrown horizontally from the top of a tower of height 5 m.It touches the ground at a distance of 10 m from the foot of the tower.The initial velocity of the body is $(g = 10 m s^{2})$