Kinematics Question 659

Question: A 2 m wide truck is moving with a uniform speed v0= 8 m/s along a straight horizontal road. A pedestrain starts to cross the road with a uniform speed v when the truck it’s 4 m away from him. The minimum value of v so that he can cross the road safely it’s

Options:

A) 2.62 m/s

B)4.6 m/s

C) 3.57 m/s

D)1.414 m/s

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Answer:

Correct Answer: C

Solution:

[c] Let the man starts crossing the road at an angle θ .

For safe crossing the condition it’s that the man must cross the road by the time the truck describes the distance 4 + AC or 4+2cotθ ..

4+2cotθg=2/sinθv or v=82sinθ+cosθ(i)

For minimum v, dvdθ=0

or8(2cosθsinθ)(2sin+cosθ)2=0

or 2cosθsinθ=0 or tanθ=2

From equation (i),

vmin=82(25)+15=85=3.57 m/s



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