Kinematics Question 643

Question:A body is thrown horizontally with a velocity $ \sqrt{2gh} $ from the top of a tower of height h. It strikes the level ground through the foot of the tower at a distance x from the tower. The value of x it’s

Options:

A) $ h $

B)$ h/2 $

C) $ ~2h~ $

D)$ 2h/3 $

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Answer:

Correct Answer: C

Solution:

[c] Using equation to trajectory $ -h=x\tan (0{}^\circ )-\frac{gx^{2}}{2(2gh)({{\cos }^{2}}0{}^\circ )} $

$ \Rightarrow x=2h $



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