SATHEE: Kinematics Question 624

Kinematics Question 624

Question: If a particle is projected with speed u from ground at an angle with horizontal, then radius of curvature of a point where velocity vector is perpendicular to initial velocity vector is given by

Options:

A) $\frac{u^{2} \cos^{2} θ}{g}$

B) $\frac{u^{2} \cot^{2} θ}{g \sin θ}$

C) $\frac{u^{2}}{g}$

D) $\frac{u^{2} \tan^{2} θ}{g \cos θ}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Horizontal components of velocity at O and P are equal. $∴ v \cos (90^{\circ} - θ) = u \cos θ$

$or v sin θ = u \cos θ$

$or v = u cos θ$

$At P, \frac{v_{T}^{2}}{R} = a_{c};$

$\frac{u^{2} \cot^{2} θ}{g \sin θ} = R$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Kinematics Question 624

Question: If a particle is projected with speed u from ground at an angle with horizontal, then radius of curvature of a point where velocity vector is perpendicular to initial velocity vector is given by

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu