Kinematics Question 623

Question: A projectile is thrown in the upward direction making an angle of 60 with the horizontal direction with a velocity of 147ms1 . Then the time after Which is inclination with the horizontal it’s 45 , it’s

Options:

A) 15(31)s

B)15(3+1)s

C) 7.5(31)s

D)7.5(3+1)s

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Answer:

Correct Answer: C

Solution:

[c] At the two points of the trajectory during projectile motion, the horizontal component of the velocity is same. Then u cos 60 = v cos 45.

150×12=v×12 or 1502 m/s

Initially: uy=usin60=15032 m/s

Finally: vy=vsin45=1502×12=1502 m/s

But vy=uy+ayt or 1502=1503210t

10t=1502(31) or t= 7.5(31)s



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