SATHEE: Kinematics Question 620

Kinematics Question 620

Question: A projectile is fired from the surface of the earth with a velocity of 5 $m s^{- 1}$ and angle $θ$ with the horizontal. Another projectile fired from another planet with a velocity of 3 $m s^{- 1}$ at the same angle follows a trajectory Which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet it’s (in $m s^{- 2}$ ) given $g = 9 .8 m/ s^{2}$

Options:

A) 3.5

B)5.9

C) 163

D)110.8

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Horizontal range = $\frac{u^{2} \sin 2 θ}{g} so g \propto u^{2}$

$or \frac{g_{planet}}{g_{earth}} = \frac{{(u_{planet})}^{2}}{{(u_{earth})}^{2}}$

$Therefore g_{planet} = {(\frac{3}{5})}^{2} (9.8 m/ s^{2})$

$= 3.5 m/ s^{2}$

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Kinematics Question 620

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