Kinematics Question 615

Question: A body projected at an angle with the horizontal has a range 300 m. If the time of flight it’s 6 s, then the horizontal component of velocity is

Options:

A) $ 30\text{ m}{{\text{s}}^{-1}} $

B)$ 50\text{ m}{{\text{s}}^{-1}} $

C) $ 40\text{ m}{{\text{s}}^{-1}} $

D)$ 45\text{ m}{{\text{s}}^{-1}} $

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Answer:

Correct Answer: B

Solution:

[b] As we know, $ \text{R = u cos}\theta \times \text{t} $

$ \text{Given, R}\text{=}\text{300}\text{m, t}\text{=}\text{6s} $

$ \therefore \text{u cos}\theta \text{=}\frac{\text{R}}{\text{t}}=\frac{300}{6}=50\text{ m}{{\text{s}}^{-1}} $



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