Kinematics Question 613

Question: A projectile is thrown in the upward direction making an angle of 60 with the horizontal direction with a velocity of 147ms1 . Then the time after Which is inclination with the horizontal it’s 45 , it’s

Options:

A) 15 s

B)10.98 s

C) 5.49 s

D)2.74 s

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Answer:

Correct Answer: C

Solution:

[c] Velocity of projectile u = 147 ms1

Angle of projection α=60

Let, the time taken by the projectile from O to A be t where direction β=45 .

As horizontal component of velocity remains constant during the projectile motion.

vcos45=u cos60

v×12=147×12v=1472ms1

For Vertical motion, vy=uygt

vsin45=45sin609.8t

1472×12=147×329.8t

9.8t=1472(31)t=5.49s



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